Two coils A and B have mutual inductance `2xx10^(2)` henry if the current in he primary is i=5 sin `10^(pi)` t then the maximum value of emf induced in coil B is
A
`pi` volt
B
`(pi)/(2)` volt
C
`(pi)/(3)` volt
D
`(pi)/(4)` volt
Text Solution
Verified by Experts
The correct Answer is:
c
`M=2xx10^(-2)H` and `i=5 sin 10pi` t induced emf `e_(B)=-M(dL_(A))/(dt)` where `e_(B)` =emf in coil B `e_(B)=-2xx10^(-2)(d)/(dt)[5 som 10pi t]` `e_(B)=-pi[cos 10 pi t]` The maximum value of emf induced in coil `B=pi V`
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