In young double slit experiment the ratio of intentsities of bright and dark bands is 16 which means
A
the ratio of their amplitudes is 5
B
intensities of individual sources are 25 and 9 units respiectively
C
the ratio of their amplitudes is 4
D
intensities of individual sources are 4 and 3 units respectively
Text Solution
Verified by Experts
The correct Answer is:
B
`(I_(max))/(I_(min))=16/1=sqrt(I_(1)+sqrt(I_(2))/sqrt(I_(1)-sqrt(i_(2))^(2)=(a_(1)+a_(2))/(a_(1)-a_(2))^(2)` where `a_(1)` and `a_(2)` are the amplitudes of the waves take part in the superposition `(a_(1)+a_(2))/(a_(1)-a_(2))^(2)=16/1 rarr (a_(1)+a_(2))/(a_(1)-a_(2))=4/1` `a_(1)+a_(2)=4a_(1)-4a_(2) rarr 5a_(2)=3a_(1)` `sqrt(I_(1))/sqrt(I_(2))=5/3 rarr (I_(1))/(I_(2))=25/9`
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