The capacity of a parallel plate air capacitor is `2 mu F` and voltage beteen the plates is changing at the rate of 3 v/s the displacement current in the capacitor is
A
`2 muA`
B
`3 mu A`
C
`5 muA`
D
`6 muA`
Text Solution
Verified by Experts
The correct Answer is:
a
The displacement current can be found as displacement current = conduction current `I_(d) =(d)/(dt)CV=c(d)/(dt)V` `I_(D)=2xx10^(-6)xxx3=6muA`
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