Calculate the work done during compression of 2 mol of an ideal gas from a volume of `1m^(3)` to `10 dm^(3)` 300 K against a pressure of 100 KPa .

Options

A. `-99 kJ`
B. `+99 kJ`
C. `+22.98 kJ`
D. `-22.98 kJ`

Answer

B

Explanation

Work done during compression,
`W = p_("ext") DeltaV`
Given, `p_(ext) = 100 K Pa, T = 300 K`
`DeltaV = V_(2) - V_(1)`
`= (10 - 1) dm^(3) = 9 dm^(3)`
`= 0.99 m^(3)`
`:. W = - 100 Kpa (0.99)m^(3)`
`=99 kJ`.