What is the quantity of hydrogen gas liberated when `46 g` sodium reacts with excess ethanol ?
(Given atomic mass of `Na = 23`)

Options

A. `2.4 xx 10^(-3) kg`
B. `2.0 xx 10^(-3) kg`
C. `4.0 xx 10^(-3) kg`
D. `2.4 xx 10^(-2) kg`

Answer

B

Explanation

The rataction of ethanol with water is as follows.
`2C_(2)H_(5)OH (l) + 2Na(s) rarr 2C_(2)H_(5)overline(O) Na^(+) +H_(2)(g) uarr`
2 moles of Na(46 g) = 1 mole of `H_(2)`
`= 2g = 2 xx 10^(-3) kg`