The osmotic pressure of solution containing `34.2 g` of cane sugar (molar mass = 342 g `mol^(-1)` ) in 1 L of solution at `20^(@)C` is (Given `R = 0.082` L atm `K^(-1) mol^(-1)` )

Options

A. `2.40 atm`
B. 3.6 atm
C. 24 atm
D. 0.0024 atm

Answer

A

Explanation

Osmotic pressure`, pi = CRT`
Where, C= concentration of solution.
Given `w = 34.3g,V = 1L , M = 342 g mol^(-1)`.
`T = 20^(@)C, = 20 + 273 = 293^(@)K`.
`:. Pi = (W)/(MV)RT = (34.2)/(342 g mol^(-1)) xx (0.082L atm K^(-1) "mol"^(-1) xx 293 K)/(1L)`
`= 2.40` atm