Home
Class 12
CHEMISTRY
What is the actual volume occupied by ...

What is the actual volume occupied by water molecules present in `20 cm^(3)` of water ?

A

`20 cm^(3)`

B

`10 cm^(3)`

C

`40 cm^(3)`

D

`24.89 cm^(3)`

Text Solution

Verified by Experts

The correct Answer is:
B

Half of the volume occupied in water is empty or unoccpied. Therefore, `10 cm^(3)` of the actual volume is occupied by water molecules present in `20 cm^(3)` of water.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • MHTCET 2016

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise Chemistry|50 Videos
  • MHTCET 2018

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise Chemistry|50 Videos

Similar Questions

Explore conceptually related problems

How many molecules of water are present in 0.9 g of water ?

Volume occupied by one molecule of water (density = 1 g cm^(-3) ) is

Knowledge Check

  • What is the actual volume occupied by watr molecules present in 20 cm^(3) of water?

    A
    20 `cm^(3)`
    B
    `10 cm^(3)`
    C
    `40 cm^(3)`
    D
    `24.49 dm^(3)`
  • The number of molecules present in 1 cm^(3) of water is :-

    A
    `2.7xx10^(19)`
    B
    `3.3xx10^(22)`
    C
    `6.02xx10^(20)`
    D
    1000
  • Volume occupied by one molecule of water (density = 1 g cm^(3) )

    A
    `3.0xx10^(-23) cm^(3)`
    B
    `5.5xx10^(-23)cm^(3)`
    C
    `9.0xx10^(-23)cm^(3)`
    D
    `6.023xx10^(-23)cm^(3)`
  • Similar Questions

    Explore conceptually related problems

    Volume occupied by one molecule of water (density "1 g cm"^(-3) ) is :

    Volume occupied by one molecule of water (density = 1g//cm^(3) ) is:

    Number of water molecules present in Mohr's salt is

    Volume occupied one molecule of water (density = 1g cm^(-3)) is :-

    How many water molecules are present in one molecule of washing soda?