`tan(alpha+beta)=sqrt(3),tan(alpha-beta)=1` then `tan 6 beta`

If A,B are acute angles such that tan(alpha+beta)=1,tan(alpha-beta)=(1)/(sqrt(3)) then tan4 alpha

If tan(2alpha+beta)=x & tan(alpha+2beta)=y , then [ tan3(alpha+beta)]. [ tan(alpha-beta)] is equal to (wherever defined)

If tan(2alpha+beta)=x & tan(alpha+2beta)=y , then [ tan3(alpha+beta)]. [ tan(alpha-beta)] is equal to (wherever defined)

If tan(2alpha+beta)=x & tan(alpha+2beta)=y , then [ tan3(alpha+beta)]. [ tan(alpha-beta)] is equal to (wherever defined)

tan(alpha+beta)=(1)/(2),tan(alpha-beta)=(1)/(3), then find the value of tan2 alpha

tan (alpha + beta) =1/2, tan(alpha - beta) = 1/3 "then the value of" tan^(2) alpha is-

If 2tan alpha=3tan beta then tan(alpha-beta)=

If 0<=alpha,beta<=90^(@) and tan(alpha+beta)=3 and tan(alpha-beta)=2 then value of sin2 alpha is

Prove that (tan alpha+tan beta)/(cot alpha+cot beta)=tan alpha tan beta

If tan (alpha+beta)=a+b and tan(alpha-beta)=a-b,thenshowtâtan alpha-b tan beta=a^(2)