Evaluate: `int (sinx)/(sqrt(36-cos ^(2)x))dx`

Explanation

We have, `int (sinx)/(sqrt(36-cos^(2)x))dx`
Let `cos x=t implies-sin x dx =dt`
Putting `sin x dx=-dt and cos x=t.`
`=-int (dt)/(sqrt(36-t^(2)))`
`=-int(dt)/(sqrt((6)^(2)-t^(2)))`
`=-sin^(-1)((t)/(6))+c`
`=-sin ^(-1)((cos x)/(6))+c`
`[becauset=cosx]`