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Find the equation of the tangent to the curve `y=3x^(2)-x+1` at P(1, 3).

A

`5x-y=2`

B

`x+5y=16`

C

`5x-y+2=0`

D

`5x=y`

Text Solution

Verified by Experts

Given curve is, `y=3x^(2)-x+1`
`(dy)/(dx)=6x-1`
at P(1,3)
`(dy)/(dx)=5`
Equation of tangent is at P(1,3) is
`y-3=(dy)/(dx)(x-1)`
`rArr y-3=5(x-1)`
`rArr y-3=5x-5`
`rArr 5x-y=2`
Hence, correct answer from the given alternatives is (a).
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