If [vec a vecb vec c] ne 0 and vecP=(ve...

If `[vec a vecb vec c] ne 0 ` and `vecP=(vec b xx vec c)/([veca vecb vec c]), vecq=(vec c xx veca)/([veca vec b vec c]), vec r =(vec a xx vec b)/([veca vecb vec c ])`, then `veca. vecp+ vecb. vecq+ vec c.vecr` is equal to …………

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The correct Answer is:

Given `vecP=(vecbxxvecc)/([vecavecbvecc]),vecq=(veccxxveca)/([vecavecbvecc])and c=(vecaxxvecb)/([vecavecbvecc])`
`therefore" "veca.vecp+vecb.vecq+vecc.vecr=veca.(vecbxxvecc)/([veca vecb vecc])+vecb.(vecc xx veca)/([veca vecb vecc])+vecc.(vecaxxvecb)/([veca vecb vecc])`
`=([vecavecbvecc])/([vecavecbvecc])+([vecavecbvecc])/([vecavecbvecc])+([vecavecbvecc])/([vecavecbvecc])`
`because veca.(vecbxxvecc)+vecb.(veccxxveca)+vecc.(vecaxxvecb)`
`=[vecavecbvecc]`
`=1+1+1=3`

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