A particle performing linear S.H.M. has maximum velocity of 25 cm/s and maximum acceleration of `100 cm//s^(2)`. Find the amplitude and period of oscillation. `(pi=3.142)`

Explanation

To solve the problem, we will use the formulas for maximum velocity and maximum acceleration in simple harmonic motion (SHM).

### Step-by-Step Solution:

1. **Identify the given values**:
- Maximum velocity, \( V_{\text{max}} = 25 \, \text{cm/s} \)
- Maximum acceleration, \( A_{\text{max}} = 100 \, \text{cm/s}^2 \)

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