The electron in the hydrogen atom is moving with a speed of `2.5 xx 10^(6)` m/s in an orbit of radius 0.5 `Å`. Magnetic moment of the revolving electron is

Explanation

Given : `v=2.3xx10^(6)m//s, r=0.53 "Å"=0.53 xx10^(-10)m`
Time period of revolution is given by,
`T=(2pi r)/(v)`
Substituting the value, we get
`T=(2xx3.14 xx0.53xx10^(-10))/(2.3xx10^(6))`
`T=(1.06xx3.142xx10^(-16))/(2.3)`
`=(3.33052xx10^(-16))/(2.3)`
`T=1.448xx10^(-16)s`