A tube open at both ends has length 47 cm. Calculate the fundamental frequency of air column. ( Neglect end correction. Speed of sound in air ` 3.3 xx 10 ^( 2 ) ` m/s ) .

Explanation

Given : Length of tube (l) = 47 cm = 0.47 m, speed of sound
(v) ` = 3.3 xx 10 ^ 2 ` m/s.
Fundamental frequency of air column in a tube open at both ends,
`n = ( v ) /( 2l ) = ( 3.3 xx 10 ^ 2 )/( 2 xx 0.47 ) = 351. 06 ` Hz