A stone of mass 2kg whirled in a horizontal circle attached at the end of 1.5 m long string. If the string makes an angle of ` 30 ^@ ` with vertical, compute its period ` ( g = 9.8 m//s ^ 2 ) ` .

Explanation

Given : Length of string (l) = 1.5 m, ` theta = 30 ^@, g = 9.8 m//s ^ 2 `
Mass of stone (m) = 2kg
Period (T) ` = 2pi sqrt ( ( lcos theta ) /( g ) ) `
` = 2 xx 3.142 sqrt ( ( 1.5 xx 1.732 ) /( 2xx 9.8 ) ) `
` = 2 xx 3.142 sqrt ( 0.1325 ) `
` = 2 xx 3.142 xx 0.3641 `
` = 2.2874 ` s