How many moles of acetic anhydride will be required to form glucose pentaacetate from 2 M of glucose ?

Options

A. 2
B. 5
C. 10
D. `2*5`

Explanation

To determine how many moles of acetic anhydride are required to form glucose pentaacetate from 2 M of glucose, we can follow these steps:

### Step 1: Understand the Reaction
Glucose reacts with acetic anhydride to form glucose pentaacetate. Each molecule of glucose can react with 5 molecules of acetic anhydride to form one molecule of glucose pentaacetate.

### Step 2: Determine the Molarity of Glucose
The question states that we have a 2 M solution of glucose. This means that in 1 liter of this solution, there are 2 moles of glucose.

### Step 3: Calculate the Moles of Acetic Anhydride Required
Since 1 mole of glucose requires 5 moles of acetic anhydride to form glucose pentaacetate, we can calculate the moles of acetic anhydride needed for 2 moles of glucose:

\[ \text{Moles of acetic anhydride} = \text{Moles of glucose} \times 5 \]

Substituting the value of moles of glucose:

\[ \text{Moles of acetic anhydride} = 2 \, \text{moles of glucose} \times 5 = 10 \, \text{moles of acetic anhydride} \]

### Conclusion
Therefore, to form glucose pentaacetate from 2 M of glucose, **10 moles of acetic anhydride** are required.

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