यदि `f(x) = (|x|)/x, x ne 0` तो साबित करें कि `|f(alpha) -f(-alpha)|=2, alphane 0`.

Explanation

`f(alpha) - f (-alpha) = (|alpha|)/(-alpha)-(-|alpha|)/(-alpha) = (|alpha|)/alpha + (|-alpha|)/alpha`
` = (|alpha|)/alpha +(|alpha|)/alpha [:' |-alpha|=|alpha|]`
` = 2 (|alpha|)/alpha = {{:(2", "alpha gt 0),(-2", " alpha lt 0):}`
इस तरह , `f(alpha) - f (-alpha) = pm 2`
`:. |f (alpha) - f (-alpha) | = |pm 2| =2`.