What volume of a solution of hydrochloric acid containing `73 g` acid per litre would suffice for the exact neutralisation of sodium hydroxide obtained by allowing `0.46 g` of metallic sodium to act upon water.

Answer

A

Explanation

`(Mw = Ew of HCl = 1 + 35.5 = 36.5)`
`underset(23 g)(Na) + H_(2) O rarr underset({:(23 + 16 + 1),(= 40 g):})(NaOH) + (1)/(2) H_(2)`
mEq of `Na = mEq of NaOH = mEq of HCl`
`(0.46)/(23) xx 1000 = (73)/(36.5) xx V (N of HCl = ("Weight")/(Ew))`
`V = 10 mL`