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A 10 mL sample of human urine was found ...

A `10 mL` sample of human urine was found to have `5 mg` of urea on analysis. Calculate the molarity of the given sample w.r.t. urea. (molecular mass of urea = 60)

Text Solution

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`M = (W_(2) xx 1000)/(Mw_(2) xx V_(sol) ("in" mL))`
`W_(2) = 5 g = 5xx10^(-3) g`
`:. M = (5 xx 10^(-3) xx 10^(3))/(60 xx 10) = 0.008`
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