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A solution contains 2.80 moles of aceton...

A solution contains 2.80 moles of acetone `(CH_(3) COCH)_(3))` and 8.20 mole of `CHCl_(3)`. Calculate the mole fraction of acetone.

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The correct Answer is:
B
`X_(2) = (n_(2))/(n_(1) + n_(2)) = (2.80)/(8.2 + 2.8) = (2.8)/(11) = 0.255`
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