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Cisplation is used an anticancer agent f...

Cisplation is used an anticancer agent for the treatment of solid tumors, and its prepared as follows:
`underset({:("Potassium tetra"),("Chloro platinate"):})(K_(2)[PtCl_(4)]) + 2NH_(3) rarr underset("Ciplatin")([Pt(NH_(3))_(2) Cl_(2)]) + 2KCl`
Given `83.0 g` of `K_(2) [PtCl_(4)]` is used with `83.0 g` of `NH_(3)`.
Atomic weights: `K = 39 , Pt = 415, Cl = 35.5 N = 14]`
The number of mol of excess reactant is

A

4.68

B

4.78

C

4.58

D

4.48

Text Solution

Verified by Experts

The correct Answer is:
D
Excess of `NH_(3)` unreacted `= 4.88 = 4.48 "mol"`
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Cisplation is used an anticancer agent for the treatment of solid tumors, and its prepared as follows: underset({:("Potassium tetra"),("Chloro platinate"):})(K_(2)[PtCl_(4)]) + 2NH_(3) rarr underset("Ciplatin")([Pt(NH_(3))_(2) Cl_(2)]) + 2KCl Given 83.0 g of K_(2) [PtCl_(4)] is used with 83.0 g of NH_(3) . Atomic weights: K = 39 , Pt = 415, Cl = 35.5 N = 14] The number of mol of K_(2) [PtCl_(4)] and NH_(3) used, respectively, are

Cisplation is used an anticancer agent for the treatment of solid tumors, and its prepared as follows: underset({:("Potassium tetra"),("Chloro platinate"):})(K_(2)[PtCl_(4)]) + 2NH_(3) rarr underset("Ciplatin")([Pt(NH_(3))_(2) Cl_(2)]) + 2KCl Given 83.0 g of K_(2) [PtCl_(4)] is used with 83.0 g of NH_(3) . Atomic weights: K = 39 , Pt = 415, Cl = 35.5 N = 14] Which reactant is the limiting reagent and which is in excess?

Cis-platin [Pt(NH_(3))_(2)Cl_(2)] , a compound used in cancer treatment is prepared by reaction of ammonia with potassium tetrachloro platinate K_(2)PtCl_(4)+2NH_(3)rarr2KCl+Pt(NH_(3))_(2)Cl_(2) (P) How many grams of cis-platin are formed from 41.5 g K_(2)Pt Cl_(4) and 34 g NH_(3) if the reaction takes place in 90 % yield ? [Ans = (x)] (Q) What is the maximum mass of KCl which can be produced if initially total 9 moles of reactant are taken. Assuming 100 % reaction. [Ans = (y)]

The correct name of |Pt(NH_(3))_(4)Cl_(2)||PtCl_(4)| is

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