Home
Class 11
CHEMISTRY
Two glucose solution are mixed. One has ...

Two glucose solution are mixed. One has a volume of `480 mL` and a c oncentration of `1.50 M` and the second has a volume of `250 mL` and concentration `1.20 M`. The molarity of final solution is

A

`1.20 M`

B

`1.50 M`

C

`1.344 M`

D

`2.70 M`

Text Solution

Verified by Experts

The correct Answer is:
C
`M_(1) V_(1) + M_(2) V_(2) = M_(3) V_(3)`
`(V_(3) = V_(1) + V_(2))`
`1.5 xx 480 + 1.2 xx 520 = M_(3) xx 1000`
`M_(3) = 1.344 M`
Promotional Banner

Topper's Solved these Questions

  • SOME BASIC CONCEPTS AND MOLE CONCEPT

    CENGAGE CHEMISTRY|Exercise Exercises Assertion-Reasoning|10 Videos

  • SOME BASIC CONCEPTS AND MOLE CONCEPT

    CENGAGE CHEMISTRY|Exercise Exercises Integers|13 Videos

  • SOME BASIC CONCEPTS AND MOLE CONCEPT

    CENGAGE CHEMISTRY|Exercise Exercises Multiple Correct (Mole Concept In Solution)|15 Videos

  • S-BLOCK GROUP 2 - ALKALINE EARTH METALS

    CENGAGE CHEMISTRY|Exercise Ex 5.1 Objective|2 Videos

  • STATES OF MATTER

    CENGAGE CHEMISTRY|Exercise Exercises (Ture False)|25 Videos

Similar Questions

Explore conceptually related problems

Two solutions of a substance (non-electroyte) are mixed in the following manner 480 mL of 1.5M of first solution with 520 mL or 1.2M of second solution. The molarity of final solution is:

IF 250 mL of 0.25 M NaCl solution is diluted with water to a volume of 500 mL , the new concentration of the solution is ______.

IF 25 mL of 0.4M solution is diluted with water to a volume of 600 mL . The new concentration of the solution is _______.

500 ml of 2M NaCl solution was mixed with 200 ml of 2 M NaCl solution. Calculate the molarity of NaCl in final solution

1M HCl and 2 M HCl are mixed in volume ratio 4:1. What is the final molarity of HCl solution?

20 mL of 0.5 M HCl is mixed with 30 mL of 0.3 M HCl, the molarity of the resulting solution is :

Two solutions of a substance (non-electrolyte) are mixed in the following manner , 480 mL of 1.5 M [first solution ] + 520 mL of 1.2 M [second solution ] . What is the molarity of the final mixture ?

4.5 g of a compound (M.W. = 90) is required to form an aqueous solution of volume 250ml. The molarity of solution is:

CENGAGE CHEMISTRY-SOME BASIC CONCEPTS AND MOLE CONCEPT-Exercises Single Correct
  1. 10 g of CaCO(3) contains

    Text Solution

    |

  2. A candle is burnt in a beaker until extinguishers itseft. A sample of ...

    Text Solution

    |

  3. Two glucose solution are mixed. One has a volume of 480 mL and a c onc...

    Text Solution

    |

  4. 1.0 g of a monobasic acid when completely acted upon Mg gave 1.301 g o...

    Text Solution

    |

  5. 0.1 g of metal combines with 46.6 mL of oxygen at STP. The equivalent ...

    Text Solution

    |

  6. The vapour density of chloride of an element is 39.5. The Ew of the el...

    Text Solution

    |

  7. The Mw of a oxide of an element is 44. The Ew of the element is 14. Th...

    Text Solution

    |

  8. Potassium selenate is isomorphous with potassium sulphate and contains...

    Text Solution

    |

  9. The Ew of an element is 13. It forms an acidic oxide which KOH forms a...

    Text Solution

    |

  10. 0.05 g of a piece of metal in dilute acid gave 24.62 mL of H(2) at 27^...

    Text Solution

    |

  11. An element A (atomic weight = 12) and B (atomic weight = 35.5) combine...

    Text Solution

    |

  12. If 1L of O(2) at 15^(@)C and 750 mm pressure contains N molecules, the...

    Text Solution

    |

  13. When 2 g of a gas A is introduced into an evacuated flask kept at 25^(...

    Text Solution

    |

  14. How many moles of ferric alum (NH(4))(2) SO(4) Fe(2) (SO(4))(3). 24 ...

    Text Solution

    |

  15. Suppose elements X and Y combine to form two compounds XY(2) and X(3)Y...

    Text Solution

    |

  16. In an experiment, 6.67 g of AlCl(3) was produced and 0.654 g Al remai...

    Text Solution

    |

  17. Nine volumes of gaseous mixture consisting of gaseous organic compound...

    Text Solution

    |

  18. 27 g of Al will react completely with…… g of O(2)

    Text Solution

    |

  19. 2 L of air formed 1915 mL of ozonised air when passed through Brodio'...

    Text Solution

    |

  20. n-Butance (C(4)H(10)) is produced by monobromation of C(2)H(6) followe...

    Text Solution

    |