If 0.5 mole of `BaCl_(2)` mixed with 0.20 mole of `Na_(3) PO_(4)` the maximum number of moles of `Ba_(3)(PO)_(2)` then can be formed is

Options

A. 0.1
B. 0.2
C. 0.5
D. 0.7

Answer

A

Explanation

`underset(2 "mol")(3 BaCl_(2)) + underset(2 "mol")(2Na_(3)PO_(4)) rarr underset(6 "mol")(6NaCl) + underset(1 "mol")(Ba_(3) (PO_(4))_(2))`
Given `implies 0.5 "mol of" BaCl_(2)` and `0.2 "mol of" Na_(3)PO_(4)`
Find the limiting reagent:
`2 "mol of" Na_(3)PO_(4) implies 2 "mol of" BaCl_(2)`
`0.2 "mol of" Na_(3)PO_(4) implies 0.3 "mol of" BaCl_(2)`
`:. Na_(3)PO_(4)` is the limiting reagent
`:. "mol of" Na_(3)PO_(4) implies "mol of" Ba_(3) (PO_(4))_(2)`
`0.2 "mol" of NaPO_(4) implies 0.1 "mol of" Ba_(3)(PO_(4))_(2)`