Calculate the density of `NH_(3)` at `30^(@)C` and 5 atm pressure.

Options

A. `3.42 g L^(-1)`
B. `2.42 g L^(-1)`
C. `1.71 g L^(-1)`
D. `3.84 g L^(-1)`

Answer

A

Explanation

`P = (dRT)/(M)`
`d = (PM)/(Rt) = (5 xx 17)/(0.0832 xx 300) = 3.42 g L^(-1)`