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2H(2) O(2) (l) rarr 2H(2)o(l) + O(2) (g)...

`2H_(2) O_(2) (l) rarr 2H_(2)o(l) + O_(2) (g)`
`100 mL` of `X` molar `H_(2)O_(2)` gives `3L` of `O_(2)` gas under the condition when 1 moe occupies `24 L`. The value of `X` is

A

2.5

B

1

C

0.5

D

0.25

Text Solution

Verified by Experts

The correct Answer is:
D
`2H_(2)O_(2) (l) rarr 2H_(2) P (l) + O_(2) (g)`
`24 L O_(2) = 1 "mol" O_(2)`
`3 L O_(2) = (1)/(8) "mol" O_(2) = (1)/(4) "mol" H_(2)O_(2) "in" mL`
`2.5 "mol" H_(2) O_(2) L^(-1)`
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