The reaction between yttrium metal and dilute `HCl` produces `H_(2) (g)` and `Y^(3+)` ions. The molar ratio of yttrium to that hydrogen produced is

Options

A. `2 : 3`
B. `3 : 2`
C. ` 1 : 2`
D. `2 : 1`

Answer

A

Explanation

`2 Y rarr 2Y^(3+) + 6e^(-) (Y rarr Y^(3+) + 3e^(-))`, (`n` factor = 3)
`6H^(o+) + 6e^(-) rarr 3H_(2) (2H^(O+) + 2e^(-) rarr H_(2))`, (`n` factor = 2)
1 eq of `Y = 1` eq of `H_(2)`
`(n = 3)` `(n = 2)`
`(1)/(3) "mol" Y = (1)/(2) "mol" H_(2)`
`:. Y : H_(2) 2 : 3`