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To prepare 100 g of a 92% by weight solu...

To prepare `100 g` of a 92% by weight solution of `NaOH` how many `g` of `H_(2) O`is needed?

Text Solution

Verified by Experts

Weight of `NaOH = ((92 g)/(100 g "solution")) (100 g "solution")`
`= 92 g NaOH`
Weight of `H_(2) O = 100 - 92 = 8.0 g H_(2) O`
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