`cosx+cosy+cosz=0"and sinx+siny+sinz`,then `cos^2((x-y)/2)=`

If cosx + cosy + cosz = 0 "and" sinx + siny + sinz =0, "then show that" cos (x-y) + cos(y - z) + cos(z - x) = - 3/2.

If cosx+cosy+cosz=0 and sinx+siny+sinz=0 then show that cos(x-y)+cos(y-z)+cos(z-x)=-3/2

If cosx+cosy+cosz=sinx+siny+sinz=0" then "cos(x-y)=

If cosx+cosy+cosz=sinx+siny+sinz=0" then "cos(x-y)=

If cosx + cosy + cosz = 0 and sinx + siny + sinz =0 , then show that cos (x-y) + cos(y - z) + cos(z - x) = - 3/2.

If cosx+cosy+cosalpha=0 and sinx+siny+sinalpha=0 then cot((x+y)/2)=

If cosx+cosy+cosalpha=0 and sinx+siny+sinalpha=0 then cot((x+y)/2)=

If cosx+cosy+cosalpha=0 and sinx+siny+sinalpha=0 then cot((x+y)/2)= ................. A) sin alpha B) cos alpha C) cot alpha D) sin ((x+y)/(2))

If cosx+cosy+cosz=sinx+siny+sinz=0" then "cos(x-y)= (a) 0 (b) -1/2 (c) 2 (d) 1

If cosx + cosy + cosz = 0 = sinx + siny + sinz ,then possible value of cos((x-y)/2) is (A) 4 3 1 2 (B) 4 3 2 1 (C) 3 4 2 1 (D) 3 4 1 2