For the chemical reaction
`N_(2)(g)+3H_(2)(g)hArr2NH_(3)(g)`
The correct option is:

Options

A. `3(d[H_(2)])/(dt)=2(d[NH_(3)])/(dt)`
B. `-(1)/(3)(d[H_(2)])/(dt)=-(1)/(2)(d[NH_(3)])/(dt)`
C. `-(d[N_(2)])/(dt)=2(d[NH_(3)])/(dt)`
D. `-(d[N_(2)])/(dt)=(1)/(2)(d[NH_(3)])/(dt)`

Answer

D

Explanation

For the chemical reaction
Rate of electron `=(d(N_(2)))/(dt)=-(1)/(3)(d[H_(2)])/(dt)=(1)/(2)(d(NH_(3)))/(dt)`