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If resistanceR(1) in resistance box is 3...

If resistance`R_(1)` in resistance box is `300 Omega`, then the balanced length is found to be `75.0 cm` from end `A`.The diameter of known wire is `1 mm` and length of the unknown wire is `31.4 cm`. Find the specific resistance of the unknown wire.

Text Solution

Verified by Experts

The correct Answer is:
A, B, D
`R/X =l/(100-l)`
` rArr X =((100-l)/l)R=((100-75)/(75))(300)=100 Omega`
Now, `X=(rhol)/A=(rhol)/((pid^2//4))`
`:. rho =(pid^2X)/(4l)`
=`((22//7)(10^-3)^2(100))/((4)(0.314)`
=`2.5 xx 10^(-4) Omega-m`.
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