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The torque of force F =(2hati-3hatj+4hat...

The torque of force `F =(2hati-3hatj+4hatk)` newton acting at the point `r=(3hati+2hatj+3hatk)` metre about origin is (in N-m)

A

`6hati-6 hatj+12 hatk`

B

`17 hati-6hatj-13hatk`

C

`-6hati+6hatj-12hatk`

D

`-17hati+6hatj+13hatk`

Text Solution

Verified by Experts

The correct Answer is:
B
`tau=rxxF`
`=|(hati, hatj ,hatk),(3,2,3),(2,-3,4)|`
`=hati (8+9)+hatj (6-12) + hatk (-9-4)`
`=(17hati - 6hatj - 13hatk) N-m`
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