Home
Class 11
PHYSICS
The motion of a particle along a straigh...

The motion of a particle along a straight line is described by the function `x=(2t -3)^2,` where x is in metres and t is in seconds. Find
(a) the position, velocity and acceleration at `t=2 s.`
(b) the velocity of the particle at the origin .

A

`1` , `0` , `4`

B

`1` , `4` , `0`

C

`10` , `14` , `-3/4`

D

`10` , `-1` , `0`

Text Solution

Verified by Experts

The correct Answer is:
B
(a) Position, `x=(2t-3)^2`
velocity, `v=(dx)/(dt)=4(2t-3) m//s`
and accleration, `a=(dv)/(dt)=8 m//s^2`
At `t=2s,`
`x=(2xx2-3)^2`
`=1.0 m`
`v=4(2xx2-3)`
`=4 m//s`
and `=8 m//s^2`
(b) At origin, `x=0`
or `(2t-3)=0`
`:. v=4xx0=0`
Promotional Banner

Topper's Solved these Questions

  • KINEMATICS

    DC PANDEY|Exercise Exercise 6.7|3 Videos

  • KINEMATICS

    DC PANDEY|Exercise Exercise 6.8|5 Videos

  • KINEMATICS

    DC PANDEY|Exercise Exercise 6.5|10 Videos

  • GRAVITATION

    DC PANDEY|Exercise (C) Chapter Exercises|45 Videos

  • KINEMATICS 1

    DC PANDEY|Exercise INTEGER_TYPE|15 Videos

Similar Questions

Explore conceptually related problems

The motion of a particle along a straight line is described by equation : x = 8 + 12 t - t^3 where x is in metre and t in second. The retardation of the particle when its velocity becomes zero is.

The motion of a particle along a straight line is described by the equation: x=8+12t-t^(3) , where x is inmeter and t in second. (i) the initial velocity of particle is 12 m//s (ii) the retardation of particle when velocity is zero is 12 m//s^(2) (iii) when acceleration is zero, displacement is 8 m the maximum velocity of particle is 12 m//s

A particle moves along a straight line such that its position x at any time t is x=3t^(2)-t^(3) , where x is in metre and t in second the

The position of a particle moving along a straight line is defined by the relation, x=t^(3)-6t^(2)-15t+40 where x is in meters and t in seconds.The distance travelled by the particle from t=0 to t=2 s is?

The displacement of a particle moving in a straight line is described by the relation s=6+12t-2t^(2) . Here s is in metre and t in second. The distance covered by the particle in first 5s is

The displacement of a particle moving in a straight line, is given by s = 2t^2 + 2t + 4 where s is in metres and t in seconds. The acceleration of the particle is.

A particle is moving along straight line whose position x at time t is described by x = t^(3) - t^(2) where x is in meters and t is in seconds . Then the average acceleration from t = 2 sec. to t = 4 sec, is :