Home
Class 11
PHYSICS
The velocity of a particle moving in a s...

The velocity of a particle moving in a straight line is directly proportional to `3//4th` power of time elapsed. How does its displacement and acceleration depend on time?

Text Solution

Verified by Experts

The correct Answer is:
A, D
`v prop t^(3/4)`
`a=(dv)/(dt)rArr a prop t^(-1/4)`
`s=int vdt rArr spropt^(7/4)`
Promotional Banner

Topper's Solved these Questions

  • KINEMATICS

    DC PANDEY|Exercise Exercise 6.7|3 Videos

  • KINEMATICS

    DC PANDEY|Exercise Exercise 6.8|5 Videos

  • KINEMATICS

    DC PANDEY|Exercise Exercise 6.5|10 Videos

  • GRAVITATION

    DC PANDEY|Exercise (C) Chapter Exercises|45 Videos

  • KINEMATICS 1

    DC PANDEY|Exercise INTEGER_TYPE|15 Videos

Similar Questions

Explore conceptually related problems

The position of a particle moving on a straight line is proportional to the cube of the time elapsed. How does the acceleration of the particle depend on time elapsed?

The velocity-time plot for a particle moving on a straight line is shown in figure.

The velocity- time plot for a particle moving on a straight line is shown in the figure

The velocity time plot for a particle moving on straight line is shown in the figure.

If average velocity of particle moving on a straight line is zero in a time interval, then

The velocity-time plot for a particle moving on a straight line is shown in the figure, then

The distance travelled by a particle in a straight line motion is directly poroportional to t^(1//2) , where t is the time elapsed.

The distance travelled by a particle in a straight line motion is directly proportional to t^(1/2) ,where t = time elapsed.The nature of motion is

The acceleration - velocity graph of a particle moving in a straight line is shown in figure. Then the slope of the velocity- displacement graph