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In the figure shown, find (a) the time...

In the figure shown, find
(a) the time when the particle strikes the ground at P.
(b) the horizontal distance QP
(c) velocity of the particle at P.

A

`6s` , `120m` , `40 m//s` , `50 m//s` `37^@`

B

`3s` , `12m` , `40 m//s` , `50 m//s` `37^@`

C

`3s` , `120m` , `4 m//s` , `50 m//s` `37^@`

D

`3s` , `120m` , `40 m//s` , `50 m//s` `37^@`

Text Solution

Verified by Experts

The correct Answer is:
D
(a)`t= sqrt((2h)/(g)) = sqrt ((2xx45)/(10)) = 3s`
(b) Horizontal distance `QP = 40t`
`= 40 xx 3 = 120m`
(c) Horizontal component of velocity at P = `40 m//s`
Vertical compound of velocity `= g t = 10t = 10 xx 3 = 30 m//s`

Net velocity v `= sqrt ((40)^2 + (30)^(2)) = 50 m//s`
`tan theta = 30/40 or 3/4 `
`:. theta = tan ^-1 (3/4) = 37^@` .
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