Home
Class 11
PHYSICS
A particle is projected from the bottom ...

A particle is projected from the bottom of an inclined plane of inclination `30^@`. At what angle `alpha `(from the horizontal) should the particle be projected to get the maximum range on the inclined plane.

Text Solution

Verified by Experts

The range is maximum at,
`alpha = pi/4 + beta/2` (given in the theory)
`=45^@ + (30^@)/2 = 60^@`.
Promotional Banner

Topper's Solved these Questions

  • PROJECTILE MOTION

    DC PANDEY|Exercise Level - 1 Assertion And Reason|10 Videos
  • PROJECTILE MOTION

    DC PANDEY|Exercise Level - 1 Single Correct|16 Videos
  • PROJECTILE MOTION

    DC PANDEY|Exercise Exercise 7.2|10 Videos
  • MOTION IN A PLANE

    DC PANDEY|Exercise (C )Medical entrances gallery|32 Videos
  • PROPERTIES OF MATTER

    DC PANDEY|Exercise Integer|8 Videos

Similar Questions

Explore conceptually related problems

A particle is projected from the bottom of an inclined plane of inclination 30^@ with velocity of 40 m//s at an angle of 60^@ with horizontal. Find the speed of the particle when its velocity vector is parallel to the plane. Take g = 10 m//s^2 .

The ratio of the range of the particle and its maximum range in the inclined plane is:

A particle is projected up an inclined plane of inclination beta at an elevation prop to nthe horizontal. Find the ratio between tan prop and tan beta , if the particle strikes the plane horizontally.

A ball is projected from the foot of an inclined plane of inclination 30^(@) at an angle 60^(@) with the horizontal,with velocity 20sqrt(3)ms^(-1) .The time after which the ball will strike the plane is

A particle is projected from surface of the inclined plane with speed u and at an angle theta with the horizontal. After some time the particle collides elastically with the smooth fixed inclined plane for the first time and subsequently moves in vertical direction. Starting from projection, find the time taken by the particle to reach maximum height. (Neglect time of collision).

A ball is projected from the bottom of an inclined plane of inclination 30^@ , with a velocity of 30 ms^(-1) , at an angle of 30^@ with the inclined plane. If g = 10 ms^(-2) , then the range of the ball on given inclined plane is

A paricle is projected up from the bottom of an inlined plane of inclination alpha with velocity v_0 If it returns to the points of projection after an elastic impact with the plane, find the total time of motion of the particle.

A projectile is projected upward with speed 2m//s on an incline plane of inclination 30^(@) at an angle of 15^(@) from the plane. Then the distance along the plane where projectile will fall is :

A particle is projected with a velocity of 20 m/s at an angle of 30^(@) to an inclined plane of inclination 30^(@) to the horizontal. The particle hits the inclined plane at an angle 30^(@) , during its journey. The time of flight is -