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In the figure shown, (a) find the forc...

In the figure shown,
(a) find the force of friction acting on the block.
(b) state whether the block will move or not. If yes then with what acceleration?

Text Solution

Verified by Experts

Resolving the force in vertical (perpendicular to the plan) direction (except friction)
Here `R` is the normal reation,
`sum F_(Y) =0 rArr R=16N`
`mu_(s)R =0.4xx16=64N`
`mu_(k)R =0.3xx16=48N`
`sum F_(x) = "net driving force" F =(12-4)N =8N`
(a) Since, `Flemu_(s)R` therefore kinetic friction or `4.8N`will act in opposite difection of `F`.
(b)Since, `Flemu_(s)R` the block will move in the direction of `F` (or downwards) with an acceleration,
`a =(F_("net"))/(m) = (F-f)/(m) = (8-4.8)/(2) =1.6m//s^(2)`
this acceleration is in the direction of `F` (or downwards).
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Knowledge Check

  • As shown in the figure , the friction force acting on the block is

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    `50 N`
    B
    `30 N`
    C
    `20 N`
    D
    None
  • In the figure shown, block of mass 2 kg is very long. Force of friction on 1 kg block is

    A
    always towards right
    B
    always towards left
    C
    is first towards right and then towards left
    D
    is first towards left and then towards right
  • A force barF=hati+4hatj acts on block shown. The force of friction acting on the block is :

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    `-hati`
    B
    `-1.8 hati`
    C
    `-2.4hati`
    D
    `-3hati`
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