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A sphere of weight w = 100N is kept stat...

A sphere of weight `w = 100N` is kept stationary on a rought inclined plane by a horizontal string `AB` as shown in figure. Find
(a)tension in the string,
(b) force of friction on the sphere and
(c)normal reation on the sphere by the plane.

Text Solution

Verified by Experts

`w = 100N`
`sum` (force in horizontal direction) = 0
`T + f cos 30^(@) = N sin 30^(@)` ...(i)
`sum` (force in horizontal direction) = 0
`N cos 30^(@) + f sin 30^(@) = 100` ...(ii)
`sum` (moment of all forces about `C`) = 0
`:. (T) (R )= f(R)`
`T = f` ...(iii)
On solving these three equation, we get
`T = f = 26.8N`
`N = 100`newton
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Knowledge Check

  • A sphere of weight W = 100 N is kept stationary on a rough inclined plane by a horizontal string AB as shown in figure. Then :

    A
    tension in th string is 100 N
    B
    normal reaction on the sphere by the plane is 100 N
    C
    tension in the string is `(100)/(2+sqrt(3))N`
    D
    fore of friction on the sphere I `(100)/(2+sqrt(3))N`
  • As shown in figure the tension in the horizontal cord is 30 N . The weight W and tension in the string OA in Newton are

    A
    `30sqrt(3),30`
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    `30sqrt(3),60`
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    `60sqrt(3),30`
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  • A weight W can be just supported on a rough inclined place by a force F either acting along the plane or horizontally. If theta is the angle of friction, then F/W is

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