For the arrangement shown in the figure, the reading of spring balance is

Options

A. `50 N`
B. `100 N`
C. `150 N`
D. None of the above

Answer

D

Explanation

`a = ("Net pulling force")/("Total mass") = (10 xx 10 - 5 xx 10)/(10 + 5) = (10)/(3) m//s ^(2)`
`5 kg` `T - 5 xx 10 = 5 xx a = (50)/(3)`
:. `T = (200)/(3) N`
This is also the reading of spring balance.