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In the system shown in figure all surfac...

In the system shown in figure all surface are smooth.Rod is moved by external agent with acceleration `9 ms^(-2)` vertically downwards.Force exerted on the rod by the wedge will be

A

`120 N`

B

`200 N`

C

`160 N`

D

`180 N`

Text Solution

Verified by Experts

The correct Answer is:
B
`(9)/(a) = tan 37^(@) = (3)/(4)`
`:. a = 12 m//s^(2)`
Let `N =` normal reation between rod and wedge.Then `N sin 37^(@)` will provide the necessary `ma` force to the wedge
`:. N sin 37^(@) = ma = (10) (12) = 120`
`N = (120)/(sin 37^(@)) = (120)/(0.6)`
`= 200 N`
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Knowledge Check

  • In the system shown in figure, all surfaces are smooth. Rod is moved by external agent with constant acceleration 9 m//s^(2) vertically downwards. Force exerted on the rod by the wedge will be :

    A
    `120 N`
    B
    `200 N`
    C
    `160 N`
    D
    `180 N`

  • All the surfaces are smooth as shown in figure. The acceleration of mass m relative to wedge is :

    A
    g sin `theta`
    B
    g sin `theta` + a cos `theta`
    C
    g sin `theta` - a cos `theta`
    D
    a cos `theta`

  • In the figure shown A and B are free to move . All the surface are smooth. Mass of A is m . Then

    A
    the acceleration of `A` will be more than `g sin theta`
    B
    the acceleration of `A` will be less than `g sin theta`
    C
    normal reation `A` due to `B` will be more than `mg cos theta`
    D
    normal reation `A` due to `B` will be less than `mg cos theta`

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