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The force required to just move a body u...

The force required to just move a body up the inclined plane is double the force required to just prevent the body from sliding down the plane. The coefficient of friction is `mu`. If `theta` is the angle of inclination of the plane than `tan theta` is equal to

A

`mu`

B

`3 mu`

C

`2 mu`

D

`0.5 mu`

Text Solution

Verified by Experts

The correct Answer is:
B

`F_(1) = mg sin theta + mu mg cos theta`
`F_(2) = mg sin theta - mu mg cos theta`
Given than `F_(1) = 2F_(2)`
:. `(mg sin theta + mu mg cos theta) = 2(mg sin theta - mu mg cos theta)`
On solving, we get `tan theta =3 mu`
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Knowledge Check

  • The force F_(1) required to just moving a body up an inclined plane is double the force F_(2) required to just prevent the body from sliding down the plane. The coefficient of friction is mu . The inclination theta of the plane is :

    A
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    C
    `tan^(-1)2mu`
    D
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