A rod `OA` of mass `4 kg` is held in horizontal position by a massless string `AB` as shown in figure. Length of the rod is `2 m`. Find
(a) tension in the string
(b) net force exerted by hings on the rod. `(g = 10 m//s^(2))`

Explanation

`H = T cos 60^(@) = (T)/(2)` …(i)
`V + T sin 60^(@) = 40` …(ii)
`sum M_(0) = 0`
`40 ((1)/(2)) = T (l sin 60^(@))` or `T =(40)/(sqrt3 N`
`H =(20)/(sqrt(3)) N` and `V = 20 N`
:. Net hings force `= sqrt(H^(2) + V^(2)) = (40)/(sqrt3) N`