Two beads of equal masses `m` are attached by a string of length `sqrt2a` and are free to move in a smooth circular ring lying in a vertical plane as shown in figure.Here a is the radius of the ring.Find the tesion and acceleration of `B` just ofter the heads are released to move.

Explanation

For `A` `T cos 45^(@) = ma`
`T = sqrt2 ma` …(i)
For `B` `m g - T cos 45^(@) = ma`
:. `M g - ma= ma` or `a = (g)/(2)`
Substituting in Eq. (i) we get `T = (mg)/(sqrt2)`