A plumb bob of mass `1 kg` is hung from the ceiling of a train compartment.The train moves on an inclined plane with constant velocity. If the angle of inclined is `30^(@)`.Find the angle made by the string with the normal to the ceiling .Also ,Find the tension in the string `(g = 10 m//s^(2))`

Explanation

Constant velocity means net acceleration `= 0`. Therefore, net force should be zero . Only two forces `T` and `mg` are acting on the bob. So they should be equal and oposite.
Asked angle `theta = 30^(@)`
`T = mg = (1) (10) = 10 N`