A cube of mass `2 kg` is help stationary against a rought wall by a force `F = 40 N` passing through center `C` . Find perpenducalar distance of normal reation between wall and cube from point `C`. Side of the cube is `20 cm Take g = 10 m//s^(2)`.

Answer

5cm

Explanation

`N = F = 40 N`

Net moment about `C = 0`
:. Anti-clock wise moment of
`f =` clock wise moment of `N`
`(20) ((20)/(2)) = (40) . x`
or `x = 5 cm`