In each case `m_(1) = 4 kg` and `m_(2) = 3 kg`. If `a_(1)` and `a_(2)` and `a_(3)` are the respective acceleration of the block `m_(1)` in given situation, then

Options

A. `a_(1) gt a_(2) gt a_(3)`
B. `a_(1) gt a_(2) = a_(3)`
C. `a_(1) = a_(2) = a_(3)`
D. `a_(1) gt a_(3) gt a_(2)`

Answer

B

Explanation

`a = (m_(2)g)/(m_(1) + m_(2)) = (30)/(7) m//s^(2)`
`a_(2) = ((m_(1) + m_(2)) g)/( m_(1) + m_(2))`
`= (10)/(7) m//s^(2)`
`a_(3) = (m_(2)g - m_(2)g sin 30^(@))/(m_(1) + (m_(1))`
` = (10)/(7) m//s^(2)`
`:. a_(1) gt a_(2) = a_(3)`