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A monkey pulls the midpoint of a 10 cm l...

A monkey pulls the midpoint of a `10 cm` long light inextensible string connecting two identical objects `A` and `B` lying on smooth table of masses `0.3 kg` continuously along the perpendicular objects of line joining the masses .The masses are found to apporoach each other at a relative acceleration of `5 m s^(-2)` when they are `6 cm` apart .The constant force applied by monkey is

A

`4 N`

B

`2 N`

C

`3 N`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B

Relative acceleration

`a_(r) = 2a`
`:. a = (a_(r))/(2) = 2.5 m//s^(2)`
At point `p`
`2 T cos theta = F`
`:. T = (F)/(2 cos theta)`
At mass `m`
component of `T` along the other mass `m` is `T sin theta`
`:. a = (T sin theta)/(m) = ((F)/(2 cos theta)) (( sin theta)/(m))`
`:. F = (2 ma)/(tan theta) = (2 xx 0.3 xx 2.5)/((3//4))`
`= 2 N`
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