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The block each of mass 1 kg are placed a...

The block each of mass `1 kg` are placed as shown .They are connected by a string which passes over a smooth (massless) pulley.

There is no friction between `m_(1)` and the ground.The coefficient of friction between `m_(1)` and`m_(2)` is `0.2 A` force `F` is applied to `m_(2)`. Which of the fpllowing statement is/are correct?

A

The system will be in equilibrium if `F le 4 N`

B

`F ge 4 N` tension in the string will be `4 N`

C

`F ge 4 N` the frictional force between the blocks will be `2 N`

D

`F = 6 N` tension in the string will be `3 N`

Text Solution

Verified by Experts

The correct Answer is:
A, C, D

Maximum value of friction between two blocks

`f_(max) = 0.2 xx 1 xx 10 = 2 N`
In critical case ,
`T = 2 N`
`F = T + 2 = 4 N`
`:.` System is in equation if `f le 4 N`
For `F gt 4 N`
`F - (T + 2) = m_(2)a = (1) (a)` ...(i)
`T - 2 = m_(2)a = (1) (a)` ...(ii)

On solving two equations, we get
`T = (F)/(2)`
when `F = 6 N, T = 3 N`
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