In the figure shown `A` and `B` are free to move . All the surface are smooth. Mass of `A is m`. Then

Options

A. the acceleration of `A` will be more than `g sin theta`
B. the acceleration of `A` will be less than `g sin theta`
C. normal reation `A` due to `B` will be more than `mg cos theta`
D. normal reation `A` due to `B` will be less than `mg cos theta`

Answer

A, D

Explanation

`a = (mg sin theta)/(m) = g sin theta`

It is also moving in `y-`direction
`:. Mg cos theta gt N`
`a_(y) = (Mg cos theta - N)/(m)`

Now `a = sqrt(a_(x)^(2) + a_(y)^(2)) gt g sin theta`