A block of mass `1 kg` is at rest relative to a smooth wedge moving leftwards with constant acceleration `a = 5 m//s^(-2)` .Let `N` be the normal reation between the block and the wedge . Then `(g = 10 m//s^(-2))`

Options

A. `N = 5sqrt5` newton
B. `N = 15` newton
C. `tan theta = (1)/(2)`
D. `tan theta = 2`

Answer

A, C

Explanation

`N cos theta = mg = 10` …(i)
`N sin theta = ma = 5` …(ii)
On solving these two equations, we get

`N = 5 sqrt5 N` and `tan theta = (1)/(2)`