A body is displaced from, `r_A=(2hati + 4hatj-6hatk) m` to `r_(B)=(6hati-4hatj + 2hatk)m` under a constant force, ` F=(2hati + 3hatj-hatk)N`. Find the work done.
DC PANDEY|Exercise Integer Type Question|11 Videos
WORK, ENERGY AND POWER
DC PANDEY|Exercise MEDICAL ENTRACES GALLERY|33 Videos
Similar Questions
Explore conceptually related problems
A block is displaced from (1m, 4m, 6m) to (2hati+3hatj-4hatk) m under a constant force F=(6hati-2hatj + hatk) N . Find the work done by this force.
A body moves from a position vec(r_(1))=(2hati-3hatj-4hatk) m to a position vec(r_(2))=(3hati-4hatj+5hatk)m under the influence of a constant force vecF=(4hati+hatj+6hatk)N . The work done by the force is :
A particle moves from position r_1=(3hati+2hatj-6hatk) m to position r_2=(14hati+13hatj+9hatk) m under the action of a force (4hati+hatj-3hatk) N , then the work done is
A particle is displaced from a position 2hati-hatj+hatk (m) to another position 3hati+2hatj-2hatk (m) under the action of a force 2hati+hatj-hatk(N) . The work done by the force is
A particle moved from position vec r_(1) = 3 hati + 2 hatj - 6 hatk to position vecr_(2) = 14 hati + 13 hatj +9 hatk undre the action of a force (4 hati + hatj +3 hatk) newtons . Find the work done .
A constant force of (2hati+3hatj+5hatk) N produces a displacement of (3hati+2hatj+2hatk) m. Then work done is
A force vecF=(2hati+3hatj+4hatk)N displaces a body from position vector vec(r_(1))=(2hati+3hatj+hatk)m to the positive vector vec(r_(2))=(hati+hatj+hatk)m . Find the work done by this force.
DC PANDEY-WORK, ENERGY & POWER-Level 2 Comprehension Based