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A body is displaced from, rA=(2hati + 4h...

A body is displaced from, `r_A=(2hati + 4hatj-6hatk) m` to `r_(B)=(6hati-4hatj + 2hatk)m` under a constant force, ` F=(2hati + 3hatj-hatk)N`. Find the work done.

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The correct Answer is:
B, D

`r_A=(2hati + 4hatj-6hatk) m`
` :. S=r_B - r_A`
`=(6hati - 4hatj+2hatk)-(2hati+4hatj-6hatk)`
`=4hati-8hatj+8hatj+8hatk`
`W=F*S=(2hati+3hatj-hatk).(4hati-8hatj+8hatk)=8-24-8=-24 J`.
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